Find all zeroes of the polynomial (2x 9x3 5 3x 1) if two of its zeroes are (2 +V3) and (2-y3).
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Alpha=2+v3 and and beta =2-v3
2+v3+2-v3=4
2+v3 x 2-v3= 1
[X2-4x+1] divide this the dividend by long division method than split the middle term of the quotient and u will get all the zeroes
2+v3+2-v3=4
2+v3 x 2-v3= 1
[X2-4x+1] divide this the dividend by long division method than split the middle term of the quotient and u will get all the zeroes
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