find all zeros of the polynomial 2x⁴-9x³+5x²+3x-1 if twovof its zeros are 2+root3 and 2-root3.
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Answered by
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Hii friend,
P(x) = 2X⁴ - 9X³ + 5X² + 3X -1
Let,
Alpha = 2+✓3 and Beta = 2-✓3
Alpha + Beta = 2+✓3 + 2-✓3 = 4
Alpha × Beta = (2+✓3)(2-✓3) = (2)² - (✓3)² = 4-3 = 1.
THEREFORE,
Required polynomial = X²-(Alpha+ Beta)X + Alpha × Beta.
= X²-4X+1 is the factor of polynomial 2X⁴-9X³+5X+3X-1.
DIVIDE THE POLYNOMIAL 2X⁴-9X³+5X2+3X-1 BY X²-4X+1
AND AFTER DIVING THE POLYNOMIAL... FACTORIES THE QUOTIENT... YOU WILL GET THE ALL ZEROS OF THE POLYNOMIAL...
HOPE U WILL UNDERSTAND THIS.. :-)
P(x) = 2X⁴ - 9X³ + 5X² + 3X -1
Let,
Alpha = 2+✓3 and Beta = 2-✓3
Alpha + Beta = 2+✓3 + 2-✓3 = 4
Alpha × Beta = (2+✓3)(2-✓3) = (2)² - (✓3)² = 4-3 = 1.
THEREFORE,
Required polynomial = X²-(Alpha+ Beta)X + Alpha × Beta.
= X²-4X+1 is the factor of polynomial 2X⁴-9X³+5X+3X-1.
DIVIDE THE POLYNOMIAL 2X⁴-9X³+5X2+3X-1 BY X²-4X+1
AND AFTER DIVING THE POLYNOMIAL... FACTORIES THE QUOTIENT... YOU WILL GET THE ALL ZEROS OF THE POLYNOMIAL...
HOPE U WILL UNDERSTAND THIS.. :-)
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0
hope this will help u.....
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