Question

find altitude and area of an isosceles triangle whose perimeter is 64 cm and whose base is 24 cm
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Answer 1

Answer:

Length of altitude is 16cm

Step-by-step explanation:

let , triangle ABC

AB=AC=x

BC=?

PERIMETER OF TRIANGLE

=sum of all sides

$64 = x + x + 24 \\ 64 - 24 = 2x \\ 40 = 2x \\ 40 \div 2 = x \\ 20 = x$

AB=AC=20cm

Now,

in right angle triangle ADC,

AC2 = AD2 DC2

${20 }^{2} = {ad}^{2} + {12 }^{2} \\ 400 = {y}^{2} + 144 \\ 400 - 144 = {y}^{2} \\ 256 = {y}^{2} \\ 16 = y \: \: ....taking \: square \: root$

AD=16 cm

length of altitude is 16cm.

Answer 2

Deoxyribonucleic Acid

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