Question

Find amount and compound interest on $10000 at 5% for 2 years compouded anually

Answer 1

______✨ HEY MATE ✨______

===============
SOLUTION :-
===============

➡️A = P(1+R/100)n
➡️A = $10000(1+5/100)2
➡️A = 10000*105/100*105/100
➡️A = $11,025

➡️CI = A - P
➡️CI = (11,025 - 10000)$
➡️CI = 1025$ ( answer )

$<marquee>✌️ HOPE IT HELPS ✌️$

Answer 2

$\mathcal{ANSWER}$

$\rule{300}{1}$

Correct question :-

Calculate the compound interest on Rs10000 for $\dfrac{5}{2}$years compounded anually at 6%.

$\rule{300}{1}$

Given, Principle $(P)$=$10000$Time$(n)=$$\dfrac{5}{2}$,Rate $r=$6%

$\rule{300}{1}$

Rate will be 6% for 2years but for $\dfrac{1}{2}$year rate will be $\rightarrow$$\dfrac{1}{2}\times{6}$$=3$%

$\rule{300}{1}$

so, $Amount(A)=P$1+$\dfrac{r1}{100}^{2}$1+$\dfrac{r2}{100}^{1}$

$\rightarrow$$10000({1+}\dfrac{6}{100})^{2}$$\rightarrow$$({1+}\dfrac{3}{100})$

$\rightarrow$$10000{(1+}\dfrac{3}{50}^{2}$ $({1+}\dfrac{3}{100})$

$\rightarrow$${10000}\dfrac{53}{50}^{2}$($\dfrac{103}{100}$)

$\rightarrow$${10000}\times\dfrac{53}{50}\times{53}{50}\times{103}{100}=Rs.11573.08$

$\rightarrow$$C.I=A-P$

$\rightarrow$$=Rs.1157308-Rs.10000=Rs.1573.08$

$\rule{300}{1}$

Hence, Compound interest is Rs.1573.08

$\rule{300}{1}$