Question

find amount and compound interest on 40000 in 3 years at 15/2% per annum​

Answer 1

☆ Given :

$\bigstar$ Principle = 40000

$\bigstar$ Time = 3 years

$\bigstar$ rate of interest = 15/2%

$\huge{ \mathfrak{solution}}$

$\green { \boxed{ \red{ \large \: s.i = \huge \purple{\frac{p \times r \times t}{100} }}}}$

$\large\implies \: s.i = \huge \frac{40000 \times 3 \times 15}{100 \times 2}$

$\large\implies \: 200 \times 3 \times 15$

$\bigstar$ $\large \boxed{ <strong>compound interest = 9000</strong><strong>}</strong>$

$\bigstar \red{amount = s.i \: + \:principle}\bigstar$

$\implies \: amount = 9000 + 40000$

$\bigstar$ $\large \boxed{ Amount = 49000}$

Mark me as brainliest please

Answer 2

Answer:

49000 is right answer friend