In triangle ABC, AP and BQ are the medians. If AC= BC, show that the medians AP and BQ are equal, prove that AP= BQ
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Answer:
To Prove :-
RA=1/3 AC
Construction :-
Draw PS parallel to BR to meet AC at S.
Proof :-
In Δ BCR, P is the mid-point of BC and PS is parallel to BR.
Where, S is the mid-point of CR
So, CS=SR (1)
Again, In Δ APS, Q is the mid-point of AP and QR is parallel to PS.
Where, R is the mid-point of AS.
So, ----- (2)
From equations (1) and (2),
We get, AR = RS = SC
⇒ AC=AR+RS+SC
⇒ AC=AR+AR+AR
⇒ AC=3AR
∴ AR=1/2AC
--Please refer to the attached image for clarification of diagram and points--
Attachments:
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