Question

find amount and principle when p=₹5000 r=10% n=2½ compounded annually​

Answer 1

1st year

Principal, P=Rs.5000

Time, T=1 year

Rate of interest ,R=6%

∴simple Interest , SI= 100PTR= 1005000×10×6=Rs.300

∴Amount =P+SI=Rs.5300

2nd year

Principal = Amount of 1st year=Rs.5300

Rate of interest =8%

Time =1 year

∴ Interest =1005300×1×8=Rs.424

∴ Amount =Rs.(5300+424)=Rs.5724

The interest of 2nd  year is the required compound interest. So, C.I=rs.424 and the required amount is Rs.5724

Answer 2

Answer:

Amount = 6352.5

Interest = 1352.5

Step-by-step explanation:

Compound Interest Amount

$a = p(1 + \frac{r}{100} ) {}^{n}$

Given Data p = 5000/-

r = 10%

$n = 2 \frac{1}{2}$

Compounded annulally

n=2

a = 5000(1+10/100)^2

a = 5000(11/10)^2

a = 5000 * 121/100

a = 6050

for Half Year Interest = PTR/100

P = 6050, T = 1/2, R = 10

I = 6050*(1/2)*10/100

I = 302.5

Total amount = a + I

= 6050 + 302.5

=6352.5

Total Interest = Amount - principle

= 6352.5-5000

= 1352.5