Question

find amount of rs 36000 after 2years compounded annually the rate of interest being 10percent for first year and 12percent for second year​

Answer 1

Step-by-step explanation:

Here, P=rs36000,p=10%p.a. and q=12%p.a.

Using the formula,A=P*(1+10/100)*(1+12/100),we have

Amount after 2 years

=36000*(1+10/100)*(1+12/100)

=36000*11/10*28/25

=Rs 38,192

Thus, amount after 2 years=Rs 38,192.

HOPE IT HELPS

Answer 2

Answer:

For the first year

P=Rs36,000

N=1year

R=10 %

We have S.I.=

100

PNR

=

100

36,000×1×10

=Rs3,600

And Amount at the end of first year P+S.I.=Rs36,000+Rs3,600=Rs39,600

Now, for the second year

P=Rs39,600

N=1year

R=12 %

We have S.I.=

100

PNR

=

100

39,600×1×12

=Rs4,752

And Amount at the end of second year P+S.I.=Rs39,600+Rs4,752=Rs44,352