Question

Find & so that (k-12)x²+ 2 (k-12) x + 2 = 0
he's equal roots​

Answer 1

Answer:

k=4,12

Step-by-step explanation:

If this equation has equal roots, then D=b²-4ac=0

b²-4ac = 0

[2(k-12)]² - 4(k-12)2 = 0

 4k²-96k+576 - 8k +96=0

4k²-104k+672=0

k²-26k+168=0

k²-12k-14k+168=0

k(k-12)-14(k-12)=0

(k-4)(k-12)=0

So,

k=4    or     k=12