Question

Find an acute angle θ, when (cosθ-sinθ)/(cosθ+sinθ)=(1-√3)/(1+√3).

Answer 1

$\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta} = \frac{1 - \sqrt{3} }{1 + \sqrt{3} } \\ dividing \: \: numerator \: \: and \: \: denominator \\ of \: left \: \: side \: by \: \: \cos \theta \\ \frac{1 - \tan \theta}{1 + \tan \theta} = \frac{1 - \sqrt{3} }{1 + \sqrt{3} } \\ comparing \\ \tan \theta = \sqrt{3} \\ \theta = 60 \: degree$

Answer 2

Answer:

Q= 60°

explanation is given in the images

hope it helps