Find an ap whose 2nd term is 10 and 6th tems exceed the 4th term by 12
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10
Given A2=10
A6-A4=12
a+d=10
a+(6-1)d-(a+(5-1)d)=12
You'll get
2d=12
d=6
a+6=10
so,
a=4
The ap is 4,10,16,22...
A6-A4=12
a+d=10
a+(6-1)d-(a+(5-1)d)=12
You'll get
2d=12
d=6
a+6=10
so,
a=4
The ap is 4,10,16,22...
Ribhu11:
sorry in the 4th line its a+(4-1)d instead of a+(5-1)d.
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4
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