Find remainder when 1! +2! ...95! is divided by 95
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all the number above 4! leaves 0 as remainder, because each
n! has 5 in it. so we need to find out the remainder of first 4 factorials
=>1!+2!+3!+4!
=1+2+6+24
=33
33 when divided by 5 leaves 3 as remainder.
ans 3
n! has 5 in it. so we need to find out the remainder of first 4 factorials
=>1!+2!+3!+4!
=1+2+6+24
=33
33 when divided by 5 leaves 3 as remainder.
ans 3
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