Question

find an ap. whose 2nd term is 10 and the 6th term exceeds the 4th term by 12

Answer 1

HEY
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HERE IS YOUR ANSWER
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AP
4 ,10,16,22,28,34

Answer 2

$\huge\sf{\underline{\underline{Solution:}}}$

Given :-

• 2nd term is 10 and the 6th term exceeds the 4th term by 12.

To Find :-

• A.P

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⇒ a + 5d = a + 3d  +12

⇒ 5d - 3d = 12

⇒ 2d = 12

⇒ d = 12/2

⇒ d = 6

⇒ a + d = 10

⇒ a + 6 = 10  

⇒ a = 10 - 6

⇒ a = 4

Now Finding 6th and 4th term

6th Term

⇒a + 5d

⇒ 4 + 5(6)

⇒4 + 30

⇒30

4th Term

⇒a + 3d

⇒4 + 3(6)

⇒4 + 18

⇒22

Hence, the terms of A.P are 4, 10, 16, 22, 28 etc