find an equation of normal line to the curve Y is equal to x cube + 2 X + 6 which is parallel to the line X + 14 Y + 4 equal to zero
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gradient of normal = gradient of parallel line
14y= - 4 - x
y= - x/14 - 2/7
gradient = - 1/14
gradient of tangent = 14 = dy/dx
y=x square + 2x + 6 -------(1)
dy/dx= 2x+2
14 = 2x + 2
x = 6
sub x = 6 into (1)
y =54
equation of normal = y - 54 = -1/14(x-6)
14y= - 4 - x
y= - x/14 - 2/7
gradient = - 1/14
gradient of tangent = 14 = dy/dx
y=x square + 2x + 6 -------(1)
dy/dx= 2x+2
14 = 2x + 2
x = 6
sub x = 6 into (1)
y =54
equation of normal = y - 54 = -1/14(x-6)
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