Find an equation of the tangent line to thegraph of y=g (x) at x=5 if g (5)=-3 & g'(5)=4
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G'(5) = 4
gradient = 4 =y
m = (y1 - y2)/(x1 - x2)
4=(y - (-3))/(x - (-5))
4 = (y + 3)/ (x - 5)
4(x - 5) = (y + 3)
4x - 20 = y + 3
y -4x +23 =0
gradient = 4 =y
m = (y1 - y2)/(x1 - x2)
4=(y - (-3))/(x - (-5))
4 = (y + 3)/ (x - 5)
4(x - 5) = (y + 3)
4x - 20 = y + 3
y -4x +23 =0
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