find an integer a such that (a)3+a=0 (b) -11+a=0
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Answered by
2
Answer:
a) 3+ a = 0
adding -a both sides
3+a-a = -a
3+0 = -a
multiplying both sides by -1
-3 = a
b) -11 + a = 0
-11+a-a = -a
-11 = -a
11 = a
Answered by
1
Answer:
a.)3 + a = o
Therefore a = o - 3 = -3
b.) -11 + a = o
Therefore a = o + 11 = 11
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