Question

find an integer a such that (a)3+a=0 (b) -11+a=0​

Answer 1

Answer:

a) 3+ a = 0

adding -a both sides

3+a-a = -a

3+0 = -a

multiplying both sides by -1

-3 = a

b) -11 + a = 0

-11+a-a = -a

-11 = -a

11 = a

Answer 2

Answer:

a.)3 + a = o

Therefore a = o - 3 = -3

b.) -11 + a = o

Therefore a = o + 11 = 11