Find an integer such that when you subtract -8 from it, you get sum a sum of 10 and -18
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3
Integer be ,I = x
x - 8 = 10 - 18
x - 8 = -8
x = 8 - 8
x = 0
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0
Answer:
Let the integer be x,
According to question,
x-(-8) = 10+(-18)
x+8 = -8
On transposing 8 from LHS to RHS
x = -8-8
x = -16
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