find an irrational number between 5by7and7by9 how many more there may be
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Answered by
3
LCM of 7,9 = 63
5/7 = 45/63 and 7/9 = 49/63
an irrational number doesn't terminate nor repeat, so
45.4554555455554555............................./63
5/7 = 45/63 and 7/9 = 49/63
an irrational number doesn't terminate nor repeat, so
45.4554555455554555............................./63
Answered by
1
Naturally we get infinite irrational numbers from it
here given that 5/7 and 7/9
then root 5/7 and 7/9 =root 5 / root 9
=root 5 /3
therefore, its the solution
here given that 5/7 and 7/9
then root 5/7 and 7/9 =root 5 / root 9
=root 5 /3
therefore, its the solution
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