Question

Find and write the output of the following python code: 2 List = ["P", 20, "R", 10, "S", 30] Times = 0 Alpha = ""Sum = 0 for I in range(1, 6, 2): Times = Times + I Alpha = Alpha + List[I -1] + "#" Sum = Sum + List[I] print(Times, Sum, Alpha)

Answer 1

Explanation:

the output of the following python code: 2 List = ["P", 20, "R", 10, "S", 30] Times = 0 Alpha = ""Sum = 0 for I in range(1, 6, 2): Times = Times + I Alpha = Alpha + List[I -1] + "#" Sum = Sum + List[I] print(Times, Sum, Alpha)

Answer 2

Given :

List = ["P" , 20 , "R" , 10 , "S" , 30]

Times = 0  

Alpha = ""

Sum = 0

for I in range(1 , 6 , 2):

   Times = Times + I

   Alpha = Alpha + List[I -1] + "#"

   Sum = Sum + List[I]

   print(Times, Sum, Alpha)

Output :

1 20 P#

4 30 P#R#

9 60 P#R#S#

Explanation :

Step 1 :

When I = 1 < 6 True

Time = 0 + 1 = 1

Alpha = "" + List[1 - 1] + "#" = "" + List[0] + "#" = "" + "P" + "#" = "P#"

Sum = 0 + List[1] = 0 + 20 = 20

print(Times, Sum, Alpha) = 1 20 P#

Step 2 :

When I = 1 + 2 = 3 < 6 True

Time = 1 + 3 = 4

Alpha = "P#" + List[3 - 1] + "#" = "P#" + List[2] + "#" = "P#" + "R" + "#" = "P#R#"

Sum = 20 + List[3] = 20 + 10 = 30

print(Times, Sum, Alpha) = 4 30 P#R#

Step 3 :

When I = 3 + 2 = 5 < 6 True

Time = 4 + 5 = 9

Alpha = "P#R#" + List[5 - 1] + "#" = "P#R#" + List[4] + "#" = "P#R#" + "S" + "#" = "P#R#S#"

Sum = 30 + List[5] = 30 + 30 = 60

print(Times, Sum, Alpha) = 9 60 P#R#S#

Step 4 :

When I = 5 + 2 = 7 < 6 False

Therefore, loop will terminate.

So, output is :

1 20 P#

4 30 P#R#

9 60 P#R#S#