Find angle A angle B and angle C of triangle ABC such that 3angle A=4angle B = 6 angle C
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we have .
3 angle A = 4 angle B = 6 angle C
let 3 angle A = 4 Angle B = 6 angle C = 180°
therefore 3 angle A = K => angle A = K/3
4 Angle B = K => Angle B = K/4
6 angle C = K => angle C = K/6
=> K/3+K/4+K/6= 180 °
=> 4K + 3K + 2K == 180 °
12
=> 9K
12
=> K = 180° × 12 = 240°
9
angle A = K = 240° = 80°
3 3
Angle B = K = 240 ° = 60°
4 4
angle C = K = 240 ° = 40°
6 6
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