Find angle ABC , Angle BAC and angle ACB of the triangle ABC
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12
EXTERIOR ANGLE IS EQUAL TO THE SUM OF OPPOSITE INTERIOR ANGLES
C = A+B
C = X + X
C= 2X
100= 2X
X = 50
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Answered by
13
WE KNOW THAT THE EXTERIOR ANGLE IS EQUAL TO SUM OF TWO OPPOSITE INTERIOR ANGLE
SO X+X=100
2X=100
X=50
ANGLE ABC=50
ANGLE BAC=50
ANGLE ACB= 80
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