Find angle ACB and angle ADB
using theorem : Angles in the segments of a circle are equal
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AOB is diameter of circle,
And we know that angles subtended in a semicircle is right angle.
Therefore, ∠ ACB = 90°
And with the theorem that angles in the same segment of a circle are equal we get,
∠ ADB = ∠ ACB = 90°
Therefore,
m∠ACB = 90°
m∠ADB = 90°
Hope it helped you..
Thank you !!!
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