Question

If x + y =12 and xy=14 find the value of (x^2+y^2)

Answer 1

Answer:

Given,x+y=12 and xy=14

x+y=12

Squaring both sides, we get,

(x+y)

2

=12

2

=>x

2

+y

2

+2xy=144

=>x

2

+y

2

+2(14)=144

=>x

2

+y

2

=144−28

=>x

2

+y

2

=116

Step-by-step explanation:

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