find angle aob in the picture below
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∆ aob in triangle ok i hope my answer is caract
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72°
Step-by-step explanation:
We know that, sum of the angles of a pentagon = 540°
So, ∠D = ∠E = ∠A = ∠B = ∠C = = 108°
Thus, ∠OAB = ∠OBA = = 54°
⇒ ∠AOB = 180° - (∠OAB + ∠OBA) = 180 - 108 = 72°
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