Find angle ATC (No wrong answers)
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Answer:
∠ATC = 52°
Step-by-step explanation:
In Δ BOC
OB = OC
=> ∠OBC = ∠OCB
∠COB = 76°
∠OBC + ∠OCB + ∠COB = 180°
=> ∠OBC + ∠OCB + 76° = 180°
=> 2∠OCB = 104°
=> ∠OCB = 52°
in Δ ABC
∠ABC = 90° ( angle in semicircle or by diameter)
∠ACB = ∠OCB = 52°
=> ∠CAB = 180° - 90° - 52°
=> ∠CAB = 38°
in Δ ACT
∠ACT = 90° (Tangent)
∠CAT = ∠OAB = 38° ( O & B lies on CA & AT lines)
=> ∠ATC = 180° - 90° - 38°
=> ∠ATC = 52°
HOPE IT HELPS...BUDDY!!
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