find angle BAC and angle ACB in the given figure
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hope this will help you....
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To find it first we need to find the angle ACB first
= (180°-130°) [180° because it forms a straight angle] = 50°.
therefore angle ACB is 50°.....
Now, to find angle BAC we have to add 50° and 60° and sub it from 180°
= (180°-{60°+50°}) [ 180° is the ang.sum.prop.of triangle]
= 180°-110°= 70°
so we can conclude that angle BAC is 70 and ACB is 50°.....
And to verify whether ans is correct we need to add all Angs of the triangle and see whether it is coming 180 deg or not
[60°+70°+50°] = 180°......
Therefore we can say the ans is correct.....
Hope this helps you....
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