find angle bac and angle bpc
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∠OAB = ∠OAC (Because OA = OB)
∠OAB = 50°
Similarly, ∠OAC = 30°
∠BAC = 80°
As, ABPC is a cyclic quadrilateral, ∠BPC + ∠BAC = 180°
∠BPC = 100°
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