Question

find angle BCA angle BCD angle BAC ​

Answer 1

Answer:

bca BCD bac usko aap alag alag kardo jaise bac BDC bca

Answer 2

Answer:

angle BCA = 180°-(angle BAC + angle CAB)

= 180°- (70°+100°)

=180° - 170°

=10°

Now, angle ACD = angle BAC [vertically opposite angle)

= 10°

So, angle BCD = angle (ACD + ACB) = 70° + 10° = 80°

and here in the question angle BAC is already given, that is 70°

hope this helps