Question

find angle cod
please any 1 solve it

Answer 1

LET ∠COA=∠1

     ∠COD=∠2

     ∠DOB = ∠3

∠1+∠2+∠3=180°   --------B

∠1+∠2=120°   ------1

∠2+∠3=110°   - --- 2

ADDING 1 AND 2

∠1+∠2+∠2+∠3=120+110

∠1+2∠2+∠3=230° -------A

SUBTRACTING B FROM A

∠1+2∠2+∠3-(∠1+∠2+∠3)=230-180

∠2=∠COD=50°

MARK BRAINLIEST