Question

find angle EDC angle ADE angle AED angle DEC angle DCE angle ACB​

Answer 1

Answer:

according to question :-

since angle BDC = 100

and angle DCB = 25

then using the angle sum property :-

angle BDC + angle DCB + angle ABC = 180

100+25+angle ABC = 180

angle ABC = 180-125 = 55

now since angle ABC = 55

then angle ABC + angle BAC + angle ACB = 180

55+55+25+angle ECD = 180

angle ECD = 180-135 = 45

now angle CDE = angle DCB (alternate opposite angle are always equal)

25=25

now angle CDE = 25

now if angle ABC = 55

then angle ADE is also = 55 (corresponding angles are always equal)

now

angle ADE + angle DAE + angle AED = 180

55+55-angle AED = 180

angle AED = 180-110 = 70

now angle CED = 180-angle AED (linear pair)

angle CED = 180-70 = 110

so the answers will be

angle EDC = 25

angle ADE = 55

angle AED = 70

angle DEC = 110

angle DCE = 45

angle ACB = 70

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