find angle of intersection between curves x²+ y² = 2x and y²= x
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given values : x^2+y^2=2x and y^2=x
now by differentiation :
=》2x + 2y.dy/dx =2
=》 dy/dx = (1-x) / y = m1
similarly;
=》 2y.dy/dx = 1
=》 dy/dx = 1/2y = m2
now ; for point of intersection put x=y then
we obtain :
=》 x^2-x =0
so; x = 1 and x =0
by keeping x value in any of the given equations we get y as :
=》 y = +/-1 and y =0
hence ; p1(1,+/-1) and p2(0,0)
therefore , the angle will be '0' degree
thankyou
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