find angle P of a quadrilateral PQRS whose angle R = 50° angle S = 100° degree and Angle Q 85°
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2
Answer:
R + S + Q = 235°
P = 360° - 235° = 125° (ASP of a quadrilateral).
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Answer:
p+q+r+s =360 (sum of interior angles of quadrilateral is 360)
p+ 85+50+100 =360
p=360-235
p=125
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