Find Angle W,X,Y and Z
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given that BC=BD
so LCDB =LCBD=62°=w
now, LCDA=90° because angles made on the circumference of a circle from the end points of the diameter are all 90°
therefore,
x+w=90°
x=90°-w
=90°-62°
=28°
therefore, x=28°
again, we know that the median of a isosceles triangle bisect the angle equally.
therefore, LDCB=2z
now, LDCB =180°-(w+62°)=180°-124°=56°
therefore, LDCB=56°
therefore, 2z=56°
z=28°
now in triangle ADC,
y+(x+w)+z=180°
=>y+90°+28°=180°
=>y=180°-118°
therefore, y=62°
therefore, w=62°,x=28°, y=62° and z=28°
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