find angleB
with complete explanation
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hope this helps you!!!
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Since, all the points of the quadrilateral lie on the circle, it is a cyclic quadrilateral.
We know the opposite angles of a cyclic quadrilateral are supplementary.
So , A + C = 180°
2x + 10 + y - 50 = 180°
2x + y - 40 = 180
2x + y = 220 -----(1)
Similarly, B + D = 180°
x + 20 + y - 10 = 180
x + y + 10 = 180
x + y = 170 ------(2)
Equating (1) and (2) we get,
x = 50°
So angle B = x + 20 = 50 + 20 = 70°
Hope This Helps You!
We know the opposite angles of a cyclic quadrilateral are supplementary.
So , A + C = 180°
2x + 10 + y - 50 = 180°
2x + y - 40 = 180
2x + y = 220 -----(1)
Similarly, B + D = 180°
x + 20 + y - 10 = 180
x + y + 10 = 180
x + y = 170 ------(2)
Equating (1) and (2) we get,
x = 50°
So angle B = x + 20 = 50 + 20 = 70°
Hope This Helps You!
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