find angular velocity of satelite which revovles a circular orbit of radius 35000 km and completes 1 round in 12 hr
Answers
Answered by
3
angular velocity = angular displacement /time
= 2pi r /time
= 2×22/7×35000/ 12hr
=18, 333. 33km/hr
= 2pi r /time
= 2×22/7×35000/ 12hr
=18, 333. 33km/hr
Similar questions