Physics, asked by Anonymous, 2 months ago

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Answered by Anonymous
3

Answer:

 \textsf{(c).}\sqrt{(b +  {c})^{2} +  c^{2} - 2(b + c).c.cos \theta}

Explanation:

 \textsf{a=b+c}

\textsf{net acceleration of}A=\sqrt{a²+c²+2accos(π-\theta)}

=\sqrt{(b+c)²+c²-2(b+c).c.cos\theta}

Answered by garimaupreti02
0

Explanation:

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