Math, asked by qansasiddiqua, 10 months ago

❤❤Find any four solutions of the equation 4x+3y=12❤❤

Answers

Answered by farhan6515
5

Answer:

4x + 3y = 12

= 4x = 12 - 3y

= 4x = 12 -3 × 2 (put y= 2)

= 4x = 12- 6

= 4x = 6

= x = 6/4

=x =3/2

other is

4x = 12 -3 ×-2

4x = 18

x = 18/4 =9/2

other is

4x = 12 - 3 ×3

x = 3/4

other is

4x = 12 -3 × -3

x = 21/4

so

many answer can solve by this method

Answered by sanketshahajisawant
1

Answer:

(1)put x=0 in equation

4(0)+3y=12

0+3y=12

3y=12

y=12/3

y=4

(2)put x=3 in equation

4(3)+3y=12

12+3y=12

3y=12-12

3y=0

y=0

(3) put x= -3 in equation

4(-3)+3y=12

-12+3y=12

3y=12+12

3y=24

y=24/3

y=8

(4) put x=9 in equation

4(9)+3y=12

36+3y=12

3y=12-36

3y= -24

y=-24/3

y=-8

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