Find any four solutions of the linear equation in two variables 2 (x+3) – 3 (y-1) =
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Answer:
2 (x + 3) -3 (y - 1) = 02x + 6 - 3y + 3
= 02x - 3y = -9
Solutions can be calculated as below:
(i) When x = 0, we have:-3y = -9y = 3(x, y) = (0, 3)
(ii) When y = 0, we have:2x = -9x = -4.5(x, y) = (-4.5, 0)
(iii) When y = 1, we have:2x - 3 = -92x = -6x = -3(x, y) = (-3, 1)
(iv) When y = -1, we have:2x - (-3) = -92x + 3 = -92x = -12x = -6(x, y) = (-6, -1)
The four solutions of the given equation are (0, 3), (-4.5, 0), (-3, 1), (-6, -1).
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Answer:
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