Math, asked by dolichaudhary1993, 7 months ago

find any two numbers which are divisible by 2, 3 ,4, 5 and 6 (all the numbers).​

Answers

Answered by pragyarai1801
1

Step-by-step explanation:

The number you are looking for is 420*n, where n is an integer greater than 0.

7 is prime.

6 is equal to the product of 3 and 2.

5 is prime.

4 is equal to the product of 2 and 2.

3 is prime.

2 is prime.

Therefore, in order for our number to be divisible by 7,6,5,4,3 and 2 it must be divisible by the prime factors, and hence we form our number from them. That gives us the result 7*(3*2)*5*2 = 420. You can check that this number is exactly divisible by all the required numbers. You will also find that any multiple of this number is also exactly divisible by all the required numbers.

Hope this helps.

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Answered by vanshikakeshwani111
2

Answer:

The numbers divisible by all the numbers are 60 and 120

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