find ap whose 15 term is 101 and 51 term is 281 ?
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Answer:
what ap I don't understand. please write correct questions .
Step-by-step explanation:
thanku
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Step-by-step explanation:
15th term of AP is given by a+14d, where a is the first term and d is common difference between two consecutive terms.
So a+14d=101. (1)
a+50d=281. (2)
Subtract (1) from (2) and we will get 36d = 180
so d come out to be 5
Now put this value of d in (1) we get
a+14(5) = 101
So a comes out to be 101-70 =31
AP is 31,36,41,46......
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