Question

the side BC of an equilateraltriangle ABC is parallel to x-axis . What are the slopes of its sides??​

Answer 1

Answer:

Step-by-step explanation:

slope of BC = 0

slope of AB = - slope of AC   (take care of the negative sign. it is negative because side AC slope will be taken clockwise.)

slope of AB = m = tanФ = tan60°  =  $\sqrt{3}$    (60 degrees because all angles in eq. triangle are 60)

slope of AC is then = - $\sqrt{3}$