Question

find AP whose 4th and 8th term are 43 and 95 respectively also find 12th term​

Answer 1

a + 3d = a4

a + 3d = 43 ---> (1)

a + 7d = a8

a + 7d = 95 ---> (2)

Subtracting (1) and (2) we get:

-4d = -52

=> d = 13

From equation (1)

=> a + 3(13) = 43

=> a + 39 = 43

=> a = 4

a12 = a + 11d

=> a12 = 4 + 11(13)

=> a12 = 4 + 143

=> a12 = 147

#BAL#answerwithquality

Answer 2

Answer:

T4 =a+3d

T8 = a+7d

Here t4 =43

And t8 = 95

43 = a+3d

95 = a+7d

-52=-2d

D=26

Now, 43=a+3d

Putting value of D to find A

43=a+3×26

43=a+72

A=43-72

A=-39

So t12=a+11d

T12 = -39+11×26

T12=-39+286

T12=247