Question

find are area of shaded region

Answer 1

$\underline{\textbf{Hey Mate Here Is Your Answer}}$

$\underline{\textbf{Given To ..}}$

Find Area Of A Shaded Region ( That Is ∆ ABM ) Now It's Also Given That Length Of Rectangle = 36m And

Breadth = 24m

Now Let's Move For Solution $\Longrightarrow$

$\underline{\textbf{Solution..}}$

Now According To Question $\Longrightarrow$

$\textbf{Length (AB) Of ABCD = 36cm }$

$\textbf{Breadth (BC)= 24cm }$

$\textbf{Now According To Figure A Triangle Is Standing On The Length AB Of Rectangle ABCD }$

So The$\Longrightarrow$

$\textbf{Base Of ABM = AB = 36m}$

Now Since ABCD Is Rectangle And ∆ABM Is Lying On The Base Of Rectangle $\Longrightarrow$

$\therefore$ $\textbf{Height Of ABC ( MN ) = ( BC )Breadth Of ABCD}$

Therefore We Have $\Longarrow$

$\mathbf{MN = BC = 24cm}$

So Now We Know That Area Of A Triangle Is $\Longrightarrow$

$\boxed{\mathbf{Area \:Of \:Triangle\: =\: \frac{1}{2} \times Base \: \times Height}}$

So We Know That $\Longarrow$

Here ..

$\mathbf{Base = AB = 36cm }$

$\mathbf{Height = MN = 24cm }$

Now Putting This Values In The Formula We Have $\Longrightarrow$

$\mathbf{ar (ABM )\: =\frac{1}{2}\times \:36cm \:\times\: 24cm}$

That Is $\Longarrow$

$\mathbf{ar (ABM ) = \frac{1}{2}\times 864 {cm}^{2} } \:$

Therefore We Have $\Longrightarrow$

$\boxed{\mathbf{ar (ABM ) = 432 \: {cm}^{2} } \: }$

$\underline{\textbf{Hence The Required Answer Is}}$

$\boxed{ \boxed{\mathbf{ar (ABM ) = 432 \: {cm}^{2} } \: }}$

$\Large{\bold{\mathfrak{Thanks..}}}$