find area of ∆(2,3)(-1,0)(4,5)
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Answer:
if the three vertices of a triangle are
(
x
1
,
y
1
)
,
(
x
2
,
y
2
)
&
(
x
3
,
y
3
)
then the area of triangle is
a
=
1
2
⋅
(
x
1
⋅
(
y
2
−
y
3
)
+
x
2
⋅
(
y
3
−
y
1
)
+
x
3
⋅
(
y
1
−
y
2
)
)
so
a
=
1
2
⋅
(
0
⋅
(
−
2
−
1
)
+
2
⋅
(
1
−
5
)
+
5
⋅
(
5
−
(
−
2
)
)
)
=
13.50
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