Question

Find area of a rectangle in square centimetres whose diagonal is 15 cm and breadth is 9 cm. ​

Answer 1

$\huge \mathscr{\orange {\underline{\pink{\underline {Answer:-}}}}}$

GIVEN :-

Diagonal = 15Cm.

Breadth = 9Cm.

TO FIND :-

Area of a Rectangle.

SOLUTION :-

H = 15Cm

B = 9Cm

L² = H² - B²

L² = ( 15 )² - ( 9 )²

L² = 225 - 81

L² = 144

L = 12Cm

Area of Rectangle

= L × b

= 12 × 9

= 108Cm.

• HENCE PROVED •
• I Hope it's Helpful

Answer 2

$\huge \dag \boxed{ \underline{ \mathfrak{ \purple{answer}}}}$

• Diagonal = 15Cm.
• Breadth = 9Cm.

TO FIND :-

• Area of a Rectangle.

SOLUTION :-

$\sf \: H = 15Cm$

$\sf \: B = 9Cm$

$\sf \: L² = H² - B²$

$\sf \: L² = ( 15 )² - ( 9 )²$

$\sf \: L² = 225 - 81$

$\sf \: L² = 144$

$L = 12Cm$

Area of Rectangle

$= L × b$

$= 12 × 9$

$= 108 \: cm {}^{2}$