Math, asked by para4, 1 year ago

find area of a rhombs with side 6 cm and altitude 4 cm and one doagonal is 8 cm find another one

Answers

Answered by parvd
1
heyaaa..bro..

thanx..
this question will tkae me to 4000+ points..

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see..bro..
by using pytagors theorem uh can bring out one diagonal..half..

so just double the diagional so uh will..get the..comepete diagonal.

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then bro..
as we..know the formula..of ar. of rhombus..

1/2 ^ product of diagonals.

so just put the balu uhh will get then..answer..

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any quesry aske me later 

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hope it helps you!!

thanks!!

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Anonymous: without using Pythagoras thereom, the easier method is mine
Answered by Anonymous
4
hiii!!!

here's ur answer...

given the side (base) of the rhombus is 6cm and altitude (height) is 4cm.

area of the rhombus = b × h

= 6 × 4

= 24cm²

length of one of the diagonal is 8cm.

therefore 1/2 × d1 × d2 = 24cm²

=> 1/2 × 8 × d2 = 24cm²

=> 4 × d2 = 24cm²

=> d2 = 24/4

=> d2 = 6cm

VERIFICATION:-

area of the rhombus = 1/2 × d1 × d2

= 1/2 × 8 × 6

= 4 × 6

= 24cm²

hence verified

thus the Length of another diagonal of the rhombus is 6cm.

hope this helps u..!
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