find area of a rhombs with side 6 cm and altitude 4 cm and one doagonal is 8 cm find another one
Answers
Answered by
1
heyaaa..bro..
thanx..
this question will tkae me to 4000+ points..
--------------------------------------
------------------------------------
see..bro..
by using pytagors theorem uh can bring out one diagonal..half..
so just double the diagional so uh will..get the..comepete diagonal.
=====================================================
======================================================
then bro..
as we..know the formula..of ar. of rhombus..
1/2 ^ product of diagonals.
so just put the balu uhh will get then..answer..
===========================
===================================
any quesry aske me later
..............................
hope it helps you!!
thanks!!
==============================
thanx..
this question will tkae me to 4000+ points..
--------------------------------------
------------------------------------
see..bro..
by using pytagors theorem uh can bring out one diagonal..half..
so just double the diagional so uh will..get the..comepete diagonal.
=====================================================
======================================================
then bro..
as we..know the formula..of ar. of rhombus..
1/2 ^ product of diagonals.
so just put the balu uhh will get then..answer..
===========================
===================================
any quesry aske me later
..............................
hope it helps you!!
thanks!!
==============================
Anonymous:
without using Pythagoras thereom, the easier method is mine
Answered by
4
hiii!!!
here's ur answer...
given the side (base) of the rhombus is 6cm and altitude (height) is 4cm.
area of the rhombus = b × h
= 6 × 4
= 24cm²
length of one of the diagonal is 8cm.
therefore 1/2 × d1 × d2 = 24cm²
=> 1/2 × 8 × d2 = 24cm²
=> 4 × d2 = 24cm²
=> d2 = 24/4
=> d2 = 6cm
VERIFICATION:-
area of the rhombus = 1/2 × d1 × d2
= 1/2 × 8 × 6
= 4 × 6
= 24cm²
hence verified
thus the Length of another diagonal of the rhombus is 6cm.
hope this helps u..!
here's ur answer...
given the side (base) of the rhombus is 6cm and altitude (height) is 4cm.
area of the rhombus = b × h
= 6 × 4
= 24cm²
length of one of the diagonal is 8cm.
therefore 1/2 × d1 × d2 = 24cm²
=> 1/2 × 8 × d2 = 24cm²
=> 4 × d2 = 24cm²
=> d2 = 24/4
=> d2 = 6cm
VERIFICATION:-
area of the rhombus = 1/2 × d1 × d2
= 1/2 × 8 × 6
= 4 × 6
= 24cm²
hence verified
thus the Length of another diagonal of the rhombus is 6cm.
hope this helps u..!
Similar questions