Question

Find area of a right angled triangle with base 10 cm and hypotenuse 26 cm

Answer 1

Answer:

Step-by-step explanation:

Let h be the height

By pythagoreas theorem:

(26)^2 = (10)^2 + (h)^2

676 = 100 + (h)^2

h^2 = 676-100

h^2 = 576

Take out the square root on both the sides.

h=24

Area of triangle = 1/2 * base * height

Area of triangle =1/2 * 10 * 24

Area of triangle = 5 * 24

Area of triangle = 120cm^2

Thus, the area of right angled triangle is 120cm^2.

Answer 2

Answer:

Area of triangle = 120cm^2

Step-by-step explanation:

Step-by-step explanation:

Let h be the height

By pythagoreas theorem:

(26)^2 = (10)^2 + (h)^2

676 = 100 + (h)^2

h^2 = 676-100

h^2 = 576

Take out the square root on both the sides.

h=24

Area of triangle = 1/2 * base * height

Area of triangle =1/2 * 10 * 24

Area of triangle = 5 * 24