find area of a trapezium with bases 3cm and 6cm, height 5cm slanted heights 7cm and 6cm.
Answers
Answered by
0
Answer:
A=a+b
2h=3+6
2·5=22.5cm²
Answered by
0
Answer:
44 cm²
Step-by-step explanation:
base(a)=6cm
base(b) = 5cm
height(h) = 8cm
< /strong > A < /strong > = \frac{a + b}{2} .h</strong><strong>A</strong><strong>=
2
a+b
.h
= > \frac{6 + 5}{2} \times 8=>
2
6+5
×8
= > 44 {cm}^{2} =>44cm
2
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