Math, asked by reginakirankiran, 4 months ago

find area of a trapezium with bases 3cm and 6cm, height 5cm slanted heights 7cm and 6cm.​

Answers

Answered by Anonymous
0

Answer:

A=a+b

2h=3+6

2·5=22.5cm²

Answered by mfuzail068
0

Answer:

44 cm²

Step-by-step explanation:

base(a)=6cm

base(b) = 5cm

height(h) = 8cm

< /strong > A < /strong > = \frac{a + b}{2} .h</strong><strong>A</strong><strong>=

2

a+b

.h

= > \frac{6 + 5}{2} \times 8=>

2

6+5

×8

= > 44 {cm}^{2} =>44cm

2

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