Question

Find area of a triangle having sides 10, 15 and 20 cm.​

Answer 1

Step-by-step explanation:

Let a = 10

b = 15

c= 20

s = a + b + c

2

s = 10 + 15 + 20

2

= 45

2

= 22.5

Area of triangle =

$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ \sqrt{22.5(22.5 - 10)(22.5 - 15)(22.5 - 20)} \\ \\ \sqrt{22.5 \times10.5 \times 7.5 \times 2.5 } \\ \\ 66.55cm {}^{2}$