Question

Find area of an isosceles triangle whose base is 16 cm and one of its equal sides is
10cm.​

Answer 1

Answer:

10cm

Step-by-step explanation:

I don't understand

Answer 2

THE QUESTION IS SAYING IT HAS TO BE SOLVED USING HERON'S FORMULAE... {FOR YOUR LEVEL! }

✍️SO LET'S DO IT! ✍️

ANSWER :

DIMENSIONS: {it doesn't matter whom u take a, b, c}

a=10

b=10

c=16

PERIMETER(P)=36

SEMI-PERIMETER (S) = P/2 = 18

HERON'S FORMULA:---

$\sqrt{s(s - a)(s - b)(s - c)}$

Puting values:----

$\sqrt{18(8)(8)(2)}$

Simplify for getting out of root:--

$\sqrt{{3}^{2} \times {8}^{2} \times {2}^{2} }$

Therefore:--

$area = 2 \times 3 \times 8$

{NEGLECTED -ve VALUE CAUSE IT'S AREA}

✨AREA=48 CM SQ..✨

HOPE IT HELPS! ☺

IF IT DOES --->

FOLLOW

THANK

MARK AS BRAINLIEST